2x^2+2510x=x

Solution for 2x^2+2510x=x equation:

2x^2+2510x=x

We move all terms to the left:

2x^2+2510x-(x)=0

We add all the numbers together, and all the variables

2x^2+2509x=0

a = 2; b = 2509; c = 0;
Δ = b2-4ac
Δ = 25092-4·2·0
Δ = 6295081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6295081}=2509$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2509)-2509}{2*2}=\frac{-5018}{4}
=-1254+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2509)+2509}{2*2}=\frac{0}{4}
=0
$